2011 AMC 8 Problem 12

#1
Angie, Bridget, Carlos, and Diego are seated at random around a square table, one person to a side. What is the probability that Angie and Carlos are seated opposite each other?

\(\textbf{(A) } \frac{1}{4} \qquad\textbf{(B) } \frac{1}{3} \qquad\textbf{(C) } \frac{1}{2} \qquad\textbf{(D) } \frac{2}{3} \qquad\textbf{(E) } \frac{3}{4} \)
 
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